CBSE Class 10 Mathematics Basic Sample Paper 20 2027 Solutions

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page 270 Cbse Class 10th Mathematics - Basic SP Sample Paper 20 Class - 10th Exam - 2026 - 27 Mathematics - Basic Time : 3 Hours Max. Marks : 80 General Instructions : Read the following instructions carefully and follow them: 1. This question paper contains 38 questions. 2. This Question Paper is…
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SAMPLE PAPER 20 Thus (b) is correct option. 4. For which value(s) of p, will the lines represented by the following pair of linear equations be parallel x y 3 5 - - 0 = x y p 6 2 - - 0 = (a) all real values except 10 (b) 10 (c) 5/2 (d) 1/2 AAns :  [Board Term-1 Delhi 2012] We have, x y 3 5 - - 0 =…
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page 272 Cbse Class 10th Mathematics - Basic SP c b 2 4 = − + For x x 2 1 0 2 − + = we have 2 b 4 = − & b 6 = and 1 c b 2 4 = − + c 2 6 4 # = − + c 8 = − c 1 8 9 = + = Thus (a) is correct option. 8. The centroid of the triangle whose vertices are ( , ), 3 7 - ( , ) 8 6 - and (5, 10) is (a) (0, 9)…
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SAMPLE PAPER 20 13. In the adjoining figure, OABC is a square of side 7 cm. OAC is a quadrant of a circle with O as centre. The area of the shaded region is (a) . cm 10 5 2 (b) . cm 38 5 2 (c) cm 49 2 (d) . cm 11 5 2 AAns :  Required area cm r r 4 1 7 22 2 2 2 # # = − b l cm 7 4 1 7 22 7 2 2 2 # #…
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page 274 Cbse Class 10th Mathematics - Basic SP Thus new volume is 8 times of original volume. Hence when the radius is increased by 100%, the corresponding volume becomes % 800 and thus increase is 700%. Thus (c) is correct option. 18. The median and mode respectively of a frequency distribution…
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SAMPLE PAPER 20 We have AE AB 3 2 3 2 6 4 # = = = km In right triangle , ADE DE2 3 4 2 2 = + ^ ^ h h 25 = Thus DE 5 = km 23. Find the mode of the following frequency distribution. Class 0- 10 10- 20 20- 30 30- 40 40- 50 50- 60 60- 70 Frequency 8 10 10 16 12 6 7 AAns :  [Board 2019 Delhi] Class…
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page 276 Cbse Class 10th Mathematics - Basic SP AAns :  [Board Term-2 Delhi 2016] We have PQ 6 = cm, OP OQ 6 = = cm Since PQ OP OQ = = , triangle PQO T is an equilateral triangle. Thus POQ + 60c = Now we know that POQ + and PTQ + are supplementary angle, POQ PTQ + + + 180c = PTQ + POQ 180c + = −…
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SAMPLE PAPER 20 AAns :  ] Since OAB is an equilateral triangle, we have AOB + 60c = Area of shaded region = Area of major sector + (Area of AOB ∆ − Area of minor sector) 360 300 7 22 6 4 3 12 360 60 7 22 6 2 2 2 # # # # c c = + − ^ ^ c h h m 7 660 36 3 7 132 = + − 36 3 7 528 = + cm2 29. Prove that…
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page 278 Cbse Class 10th Mathematics - Basic SP HCF (144, 90) 2 3 18 2 # = = Thus each stack would have 18 cartons. Section - D Section D consists of 4 questions of 5 marks each. 32. ,a b and c are the sides of a right triangle, where c is the hypotenuse. A circle, of radius r , touches the sides…
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SAMPLE PAPER 20 Now line (1) y x 3 7 = − x 0 2 3 y -7 -1 2 and line (2) x y 2 5 1 + + 0 = or, y x 5 1 2 = − − x 2 -3 y -1 1 Plotting the above points and drawing lines joining them, we get the following graph. Clearly, the two lines intersect at point ,2 1 - ^ h. Hence x 2 = and y 1 =− O Solve the…
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page 280 Cbse Class 10th Mathematics - Basic SP In ABC T tan45c BC AB = 1 BC h 6 = + BC h 6 = + ...(1) In DBC T , tan30c BC DB = from (1) 3 1 h h 6 = + h 3 h 6 = + ( ) h 3 1 - 6 = h 3 1 6 = − 3 1 6 3 1 3 1 # = − + + ( ) 2 6 3 1 = + ( ) 3 3 1 = + ( . ) 3 1 73 1 = + . 3 2 73 # = . m 8 19 = Thus…
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SAMPLE PAPER 20 (iii) Area, 9600 x x 2 3 # = x 6 2 = x2 6 9600 = 1600 = x 1600 = cm 40 = Width, x 2 cm 80 = Length, x 3 cm 120 = O Area of both curtains 2 2 1 40 120 # # # = b l 40 120 # = 4800 = Window area 9600 4800 100 # = % 50 = 37. Riya has a lawn with a flowerbed and grass land. The grass…
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page 282 Cbse Class 10th Mathematics - Basic SP taken simple number out of 100. It doesn’t make any difference. Total possible outcomes in all case is 100 because frequency is 100 and out of which we have to select one. Thus ( ) n S 100 = (i) Family has two or three children, Let E1 be the event…
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