CBSE Class 10 Mathematics Basic Sample Paper 13 2027 Solutions
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Page 2 of 14 ![SAMPLE PAPER 13 ( ) P E ( ) ( ) n S n E = 9 5 = Thus (c) is correct option. 7. The value of c for which the pair of equations cx y 2 − = and x y 6 2 3 − = will have is (a) 3 (b) 3 - (c) 12 - (d) no value AAns : [Board Term-1 SQP 2014] The given lines are, cx y - 2 = and x y 6 2 - 3 = Condition…](/class-10/maths-basic/answer13/p3.webp?v=1794476334)
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Page 6 of 14 ![SAMPLE PAPER 13 2 9 30 =− + 2 9 30 = − + 2 51 25 2 1 = = Hence, 21st term of given AP is 25 2 1 . 22. If , A 5 2 ^ h, , B 2 2 - ^ h and , C t 2 - ^ h are the vertices of a right angled triangle with B 90º + = , then find the value of .t AAns : [Board Term-2 Delhi 2015] As per question, triangle…](/class-10/maths-basic/answer13/p7.webp?v=1794476334)
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Page 9 of 14 ![page 182 Cbse Class 10th Mathematics - Basic SP surface area of the article. AAns : [Board 2018] Total surface Area of article = CSA of cylinder + CSA of 2 hemispheres CSA of cylinder rh 2π = . 2 7 22 3 5 10 # # # = cm 220 2 = Curved surface area of two hemispherical scoops r 2 2 2 # π = . . 4 7…](/class-10/maths-basic/answer13/p10.webp?v=1794476334)
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Page 11 of 14 ![page 184 Cbse Class 10th Mathematics - Basic SP AAns : [Board Term-1 2015] We have redrawn the given figure as below. We have AB AD + BC CD = + AD BC CD AB = + − AD h d x = + − In right , ACD T we have AD2 AC DC 2 2 = + h d x 2 + − ^ h x h d 2 2 = + + ^ h h d x x h 2 2 + − − + ^ ^ h h d2 = h d x…](/class-10/maths-basic/answer13/p12.webp?v=1794476334)
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