CBSE Class 10 Mathematics Basic Sample Paper 9 2027 Solutions

Download Question PaperAll Mathematics Basic papers
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 118 Cbse Class 10th Mathematics - Basic SP Sample Paper 09 Class - 10th Exam - 2026 - 27 Mathematics - Basic Time : 3 Hours Max. Marks : 80 General Instructions : 1. This question paper contains 38 questions. 2. This Question Paper is divided into 5 Sections A, B, C, D and E. 3. In Section A,…
Page 1 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 Given, 3x y + 81 = 3x y + 34 = x y + 4 = ...(1) and 81x y - 3 = 3 x y 4 - ^ h 31 = x y 4 - ^ h 1 = x y - 4 1 = ...(2) Adding equation (1) and (2), we get x 2 4 4 1 = + 4 17 = x 8 17 = 2 8 1 = From equation (1), we get y 8 15 = 1 8 7 = Thus (d) is correct option. 4. If the perimeter…
Page 2 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 120 Cbse Class 10th Mathematics - Basic SP Height x (in cm) Number of Students ( )f cf 150-155 15 15 155-160 13 28 160-165 10 38 165-170 08 46 170-175 09 55 175-180 08 63 N 63 = We have, N 63 = ; N 2 2 63 = . 31 5 = The cumulative frequency just greater than N 2 is 38 and the corresponding…
Page 3 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 12. A card is drawn from a deck of 52 cards. The event E is that card is not an ace of hearts. The number of outcomes favourable to E is (a) 4 (b) 13 (c) 48 (d) 51 AAns :  In a deck of 52 cards, there are 13 cards of heart and 1 is ace of heart. Hence, the number of outcomes…
Page 4 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 122 Cbse Class 10th Mathematics - Basic SP Radius of outer concentric circle, m 35 7 = + ^ h . m 42 = Area of path m 42 35 2 2 2 π = − ^ h m 7 22 42 35 2 2 2 = − ^ h Thus (c) is correct option. 18. Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance…
Page 5 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 Section - B Section B consists of 5 questions of 2 marks each. 21. Find the ratio in which the point ,k 3 - ^ h divides the line segment joining the points ,5 4 - - ^ h and , . 2 3 - ^ h Also find the value of k . AAns :  As per question, line diagram is shown below. Let AB be…
Page 6 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 124 Cbse Class 10th Mathematics - Basic SP Let the first term of an AP be a and common difference be d . Now d 7 10 3 = − =− a , n 184 7 = = 7th term from the original end, a7 a d 6 = + a7 184 6 3 = + − ^ h 184 18 166 = − = . Hence, 166 is the 7th term from the end. O The fourth term of an AP…
Page 7 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 In ABC T we have, º sin45 AC AB = 2 1 AC 10 = AC 10 2 = . 10 1 414 # = . 14 14 = m Hence, the length of wire is 14.14 m 28. Solve for x : x x 4 1 7 1 + − + 30 11 = x ,4 7 !- - . AAns :  We have x x 4 1 7 1 + − + 30 11 = ( )( ) x x x x 4 7 7 4 + + + − − 30 11 = x x x 4 7 28 3 2 + +…
Page 8 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 126 Cbse Class 10th Mathematics - Basic SP the remaining solid. AAns :  Let h and r be the height and radius of cylinder and cone. Height, h 14 = cm and radius, r 6 = cm Volume of the remaining solid, Vremain V V cylinder cone = − r h r h 3 1 2 2 π π = − r h 3 2 2 π = 3 2 7 22 6 6 14 # # # #…
Page 9 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 Now, area of quadrant, r 4 2 π . ( ) 4 1 3 14 15 2 2 # # = . 4 1 3 14 225 2 # # # = . 2 3 14 225 # = . cm 353 25 2 = Therefore, area of shaded region = Area of quadrant OPBQ - area of square OABC . 353 25 225 = − . cm 128 25 2 = 33. Find the zeroes of the quadratic polynomial y y 7…
Page 10 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 128 Cbse Class 10th Mathematics - Basic SP FB AF OX AO = ..(1) In , AXC T EC AE OX AO = ...(2) From (1) and (2) we get FB AF EC AE = By converse of BPT we have EF || BC From (1) we get OA OX AF FB = OA OX OA + AF FB AF = + OA AX AF AB = AX AO AB AF = Thus : : AO AX AF AB = Hence Proved 35. If…
Page 11 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon
SAMPLE PAPER 09 AAns :  We prepare the following frequency distribution table. Heart beats per minute Class mark xi ^ h Women fi ^ h cf u x a 3 i i = − f u i i 65-68 66.5 2 2 3 - 6 - 68-71 69.5 4 6 2 - 8 - 71-74 72.5 3 9 1 - 3 - 74-77 75.5 8 17 0 0 77-80 78.5 7 24 1 7 80-83 81.5 4 28 2 8 83-86…
Page 12 of 13
Free PDFs for every subjectDownload more free study material for CBSE and competitive exams.Download Free
page 130 Cbse Class 10th Mathematics - Basic SP We have ( , ) B 6 7 and ( , ) D 6 1 . BD ( ) ( ) 6 6 7 1 2 2 = − + − 6 = 38. Volume of a Bird Cage. A company makes rectangular shaped bird cages with height b inches and square bottoms. The volume of these cages is given by the function V b b b 6 9 3…
Page 13 of 13
Nodia Sample Paper Books 2026Chapter-wise questions, solved papers and more for CBSE board exams.Buy on Amazon

More Class 10 Mathematics Basic sample papers · Other subjects